# Line slope calculator x-2y=8

**Straight line given by points A[8; 0] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = 0.5x-4

**Canonical form of the line equation:**x-2y-8 = 0

**Parametric form of the line equation:**

x = 2t+8

y = t ; t ∈ R

**Slope:**m = 0.5

**Slope angle of line: φ =**26°33'54″ = 0.4636 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = -4

**Distance line from the origin:**d

_{0}= 3.5777

**The length of the segment AB: |AB| =**2.2361

**Vector: AB =**(2; 1)

**Normal vector: n =**(1; -2)

**Midpoint of the segment AB: M =**[9; 0.5]

**Perpendicular Bisector equation:**2x+y-18.5 = 0

**Vector OA = (8; 0) ; |OA| = 8**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 80**

**Angle ∠ AOB = 5°42'38″ = 0.0997 rad**